a-gt-0-b-gt-0-x-1-2-y-7-2-a-2-x-2-2-y-3-2-b-2-Find-a-b-min-

Question Number 183380 by Shrinava last updated on 25/Dec/22

a > 0, b > 0

{\begin{cases} {(x - 1)}^{2} + {(y - 7)}^{2} = a^{2} \\ {(x - 2)}^{2} + {(y - 3)}^{2} = b^{2} \end{cases}

Find : {(a + b)}_{\min} = ?

Commented by Frix last updated on 25/Dec/22

\sqrt{17} = the distance of the centers

If we see it as two independent circles

obviously the limit of the minimum is 0

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