A-heat-transfer-of-9-0-10-5-J-is-required-to-convert-a-block-of-ice-at-20-C-to-water-at-15-C-what-was-the-mass-of-the-block-of-ice-

Question Number 192472 by Mastermind last updated on 19/May/23

A heat transfer of 9.0 \times 10^{5} J is required

to convert a block of ice at 20 ° C to

water at 15 ° C, what was the mass of

the block of ice ?

Answered by MikeH last updated on 19/May/23

Q = {m c}_{i} (20 - 0) + m l + {m c}_{w} (15 - 0)

\Rightarrow m = \frac{Q}{20 c_{i} + l + 15 c_{w}}

c_{i} = specific heat capacity of ice

c_{w} = specific heat capacity of water

l = laten heat of fusion of ice

Commented by Mastermind last updated on 20/May/23

Thank you so much