A-large-number-of-bullets-are-fired-in-all-direction-with-same-speed-u-The-maximum-area-on-the-ground-covered-by-these-bullets-will-be-1-pi-u-2-g-2-pi-u-4-g-2-3-pi-4-u-4-g-2-4-pi-2-

FacebookTweetPin

Question Number 17999 by Tinkutara last updated on 13/Jul/17

$$\mathrm{A}\mathrm{large}\mathrm{number}\mathrm{of}\mathrm{bullets}\mathrm{are}\mathrm{fired}\mathrm{in}$$$$\mathrm{all}\mathrm{direction}\mathrm{with}\mathrm{same}\mathrm{speed}u.\mathrm{The}$$$$\mathrm{maximum}\mathrm{area}\mathrm{on}\mathrm{the}\mathrm{ground}\mathrm{covered}$$$$\mathrm{by}\mathrm{these}\mathrm{bullets}\mathrm{will}\mathrm{be}$$$$\left(1\right)\pi .\frac{u^2}{g}$$$$\left(2\right)\pi .\frac{u^4}{g^2}$$$$\left(3\right)\frac{\pi }{4}.\frac{u^4}{g^2}$$$$\left(4\right)\frac{\pi }{2}.\frac{u^4}{g^2}$$

Answered by ajfour last updated on 13/Jul/17

$$\mathrm{Range}\mathrm{is}\mathrm{then}\mathrm{a}\mathrm{maximum},\mathrm{R}=\frac{{\mathrm{u}}^2}{\mathrm{g}}$$$$\mathrm{Area}\mathrm{is}\mathrm{a}\mathrm{circle}\mathrm{of}\mathrm{radius}\mathrm{R}.$$$$\mathrm{So}\mathrm{Area}\mathrm{A}=\pi {\mathrm{R}}^2=\pi .\frac{{\mathrm{u}}^4}{{\mathrm{g}}^2};\mathrm{option}\left(2\right).$$

Commented by Tinkutara last updated on 14/Jul/17

$$\mathrm{Thanks}\mathrm{Sir}!$$

Terms of Service
Privacy Policy
Contact: info@tinkutara.com

FacebookTweetPin