Question Number 156373 by VIDDD last updated on 10/Oct/21
$$ \\ $$$$\:\:\mathrm{A}.\:\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\left[\mathrm{tan}\frac{{k}\pi}{\mathrm{2n}}\right] \\ $$
Answered by SANOGO last updated on 10/Oct/21