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Question Number 163600 by Eric002 last updated on 08/Jan/22

a l i n e c h a r g e s o f c h a r g e d e n s i t y

p l = 4 x^{3} - x + 3 m c / m l a y i n g a l o n g t h e x - a x i s .

d e t e r m i n e t h e t o t a l c h a r g e i f t h e l i n e c h a r g e

e x t e n d s f r o m x = 2 a n d x = 6 m

Answered by ajfour last updated on 08/Jan/22

△ q = \int_{2}^{6} (4 x^{3} - x + 3) d x

= {(x^{4} - \frac{x^{2}}{2} + 3 x)}_{2}^{6} \frac{m i l l i c o u l o m b}{m e t r e}

= 10 (36^{2} - 18 + 18 - 16 + 2 - 6) \frac{μ C}{c m}

= 10 (900 + 360 + 16) \frac{μ C}{c m}

= 0.012760 \frac{C}{c m} .

Commented by Eric002 last updated on 08/Jan/22

w e l l d o n e s i r

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