A-luminous-point-P-is-inside-a-circle-A-ray-emanates-from-P-and-after-two-reflections-by-the-circle-returns-to-P-If-be-the-angle-of-incidence-a-the-distance-of-P-from-the-centre-of-the-circle-a

Question Number 57664 by necx1 last updated on 09/Apr/19

A l u m i n o u s p o i n t P i s i n s i d e a c i r c l e .

A r a y e m a n a t e s f r o m P a n d a f t e r t w o

r e f l e c t i o n s b y t h e c i r c l e, r e t u r n s t o P .

I f θ b e t h e a n g l e o f i n c i d e n c e, a = t h e

d i s t a n c e o f P f r o m t h e c e n t r e o f t h e

c i r c l e a n d b = t h e d i s t a n c e o f t h e c e n t r e

f r o m t h e p o i n t w h e r e t h e r a y i n i t s

c o u r s e c r o s s e s i t s d i a m e t e r t h r o u g h P .

p r o v e t h a t \tan θ = \frac{a - b}{a + b}

Commented by mr W last updated on 10/Apr/19

n o i m a g e n o u n d e r s t a n d \dots

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