Question Number 44222 by Necxx last updated on 23/Sep/18
$${A}\:{man}\:{borrowed}\:{x}\:{at}\:\mathrm{5\%}\:{per}\:{annum} \\ $$$${simple}\:{interest}.{He}\:{paid}\:\mathrm{198000}\: \\ $$$${after}\:\mathrm{2}{years}.{Calculate}\:_{} \\ $$$$\left.{a}\right){the}\:{value}\:{of}\:{x} \\ $$$$\left.{b}\right){simple}\:{interest} \\ $$
Answered by olj55336@awsoo.com last updated on 24/Sep/18
$${taken}\:\mathrm{100}+\mathrm{5}+\mathrm{5}.\mathrm{25}\:{pay}\:{full}\:{amount} \\ $$$$\mathrm{198000}/\mathrm{110}.\mathrm{25}×\mathrm{100}=\mathrm{179591}.\mathrm{84} \\ $$$$ \\ $$
Commented by 12344 last updated on 24/Sep/18
$$\mathrm{no}\:\mathrm{no}\:\mathrm{no} \\ $$
Answered by 12344 last updated on 24/Sep/18
$$\mathrm{I}=\frac{\mathrm{PRT}}{\mathrm{100}} \\ $$$$\mathrm{cross}\:\mathrm{multiply} \\ $$$$\mathrm{I}×\mathrm{100}=\mathrm{PRT} \\ $$$$\mathrm{100I}=\mathrm{PRT} \\ $$$$\mathrm{where}\:\mathrm{P}={x}.\mathrm{R}=\mathrm{5}.\:\mathrm{T}=\mathrm{2}.\:\mathrm{I}=? \\ $$$$\mathrm{100I}={x}×\mathrm{5}×\mathrm{2} \\ $$$$\mathrm{100I}=\mathrm{x}×\mathrm{10} \\ $$$$\mathrm{100I}=\mathrm{10}{x} \\ $$$$\frac{\mathrm{100I}}{\mathrm{10}}=\frac{\mathrm{10}{x}}{\mathrm{10}} \\ $$$$\mathrm{10I}={x}……………\left(\mathrm{1}\right) \\ $$$$\:\:\:\:\:{B}\mathrm{UT} \\ $$$${x}+\mathrm{I}=\mathrm{198000}………\left(\mathrm{2}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{substitute}\:\left(\mathrm{1}\right)\:\mathrm{into}\left(\mathrm{2}\right) \\ $$$$\mathrm{10I}+\mathrm{I}=\mathrm{198000} \\ $$$$\mathrm{11I}=\mathrm{198000} \\ $$$$\frac{\mathrm{11I}}{\mathrm{11}}=\frac{\mathrm{198000}}{\mathrm{11}} \\ $$$$\mathrm{I}=\mathrm{18000} \\ $$$$\:\:\mathrm{bu}{t} \\ $$$$\mathrm{10I}={x} \\ $$$$\mathrm{10}\left(\mathrm{18000}\right)={x} \\ $$$$\mathrm{180000}={x} \\ $$$${therefore} \\ $$$$\left.\mathrm{a}\right)\:{x}=\mathrm{180000} \\ $$$$\left.\mathrm{b}\right)\mathrm{simple}\:\mathrm{interest}\left(\mathrm{I}\right)=\mathrm{18000} \\ $$
Commented by Necxx last updated on 24/Sep/18
$${Thank}\:{you}\:{so}\:{much}\:{sir} \\ $$