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A-man-is-climbing-a-ladder-which-is-inclined-to-the-wall-at-an-angle-of-30-If-he-ascends-at-a-rate-of-2-m-s-then-he-approaches-the-wall-at-the-rate-of-




Question Number 25191 by adityapratap2585@gmail.com last updated on 05/Dec/17
A man is climbing a ladder which is  inclined to the wall at an angle of 30° .  If he ascends at a rate of 2 m/s then   he approaches the wall at the rate of−
$$\mathrm{A}\:\mathrm{man}\:\mathrm{is}\:\mathrm{climbing}\:\mathrm{a}\:\mathrm{ladder}\:\mathrm{which}\:\mathrm{is} \\ $$$$\mathrm{inclined}\:\mathrm{to}\:\mathrm{the}\:\mathrm{wall}\:\mathrm{at}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{30}°\:. \\ $$$$\mathrm{If}\:\mathrm{he}\:\mathrm{ascends}\:\mathrm{at}\:\mathrm{a}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{2}\:\mathrm{m}/\mathrm{s}\:\mathrm{then}\: \\ $$$$\mathrm{he}\:\mathrm{approaches}\:\mathrm{the}\:\mathrm{wall}\:\mathrm{at}\:\mathrm{the}\:\mathrm{rate}\:\mathrm{of}− \\ $$$$ \\ $$
Commented by prakash jain last updated on 08/Dec/17
Diagonal Length=2m  Base Length=2×sin 30=1  He approaches the wall  at the rate of 1 m/s
$$\mathrm{Diagonal}\:\mathrm{Length}=\mathrm{2m} \\ $$$$\mathrm{Base}\:\mathrm{Length}=\mathrm{2}×\mathrm{sin}\:\mathrm{30}=\mathrm{1} \\ $$$$\mathrm{He}\:\mathrm{approaches}\:\mathrm{the}\:\mathrm{wall} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{1}\:\mathrm{m}/\mathrm{s} \\ $$
Commented by mrW1 last updated on 07/Dec/17
Should it not be   Base Length=2×sin 30=1 ?
$${Should}\:{it}\:{not}\:{be}\: \\ $$$$\mathrm{Base}\:\mathrm{Length}=\mathrm{2}×\mathrm{sin}\:\mathrm{30}=\mathrm{1}\:? \\ $$
Commented by prakash jain last updated on 08/Dec/17
Yes. The angle of the ladder is  with the wall,  i will correct.
$$\mathrm{Yes}.\:\mathrm{The}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ladder}\:\mathrm{is} \\ $$$$\mathrm{with}\:\mathrm{the}\:\mathrm{wall},\:\:\mathrm{i}\:\mathrm{will}\:\mathrm{correct}. \\ $$

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