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Question Number 13107 by tawa tawa last updated on 14/May/17
A man moves 20m north then 12m east and finally 15m south.  His displacement  from the starting point is ?
$$\mathrm{A}\:\mathrm{man}\:\mathrm{moves}\:\mathrm{20m}\:\mathrm{north}\:\mathrm{then}\:\mathrm{12m}\:\mathrm{east}\:\mathrm{and}\:\mathrm{finally}\:\mathrm{15m}\:\mathrm{south}.\:\:\mathrm{His}\:\mathrm{displacement} \\ $$$$\mathrm{from}\:\mathrm{the}\:\mathrm{starting}\:\mathrm{point}\:\mathrm{is}\:? \\ $$
Answered by RasheedSindhi last updated on 14/May/17
Net distance in north-south  direction 20−15=5 m  To  east 12m  If D is displacement       D=(√(12^2 +5^2 ))=(√(169))=13 m
$$\mathrm{Net}\:\mathrm{distance}\:\mathrm{in}\:\mathrm{north}-\mathrm{south} \\ $$$$\mathrm{direction}\:\mathrm{20}−\mathrm{15}=\mathrm{5}\:\mathrm{m} \\ $$$$\mathrm{To}\:\:\mathrm{east}\:\mathrm{12m} \\ $$$$\mathrm{If}\:\mathrm{D}\:\mathrm{is}\:\mathrm{displacement} \\ $$$$\:\:\:\:\:\mathrm{D}=\sqrt{\mathrm{12}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} }=\sqrt{\mathrm{169}}=\mathrm{13}\:\mathrm{m} \\ $$
Commented by tawa tawa last updated on 14/May/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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