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A-man-of-mass-85-kg-stands-on-a-lift-of-mass-30-kg-When-he-pulls-on-the-rope-he-exerts-a-force-of-400-N-on-the-floor-of-the-lift-Calculate-acceleration-of-the-lift-Given-g-10-m-s-2-




Question Number 21557 by Tinkutara last updated on 27/Sep/17
A man of mass 85 kg stands on a lift of  mass 30 kg. When he pulls on the rope,  he exerts a force of 400 N on the floor of  the lift. Calculate acceleration of the  lift. Given g = 10 m/s^2 .
$$\mathrm{A}\:\mathrm{man}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{85}\:\mathrm{kg}\:\mathrm{stands}\:\mathrm{on}\:\mathrm{a}\:\mathrm{lift}\:\mathrm{of} \\ $$$$\mathrm{mass}\:\mathrm{30}\:\mathrm{kg}.\:\mathrm{When}\:\mathrm{he}\:\mathrm{pulls}\:\mathrm{on}\:\mathrm{the}\:\mathrm{rope}, \\ $$$$\mathrm{he}\:\mathrm{exerts}\:\mathrm{a}\:\mathrm{force}\:\mathrm{of}\:\mathrm{400}\:\mathrm{N}\:\mathrm{on}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{lift}.\:\mathrm{Calculate}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{lift}.\:\mathrm{Given}\:{g}\:=\:\mathrm{10}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} . \\ $$

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