A-man-pushes-a-box-of-40kg-up-an-incline-of-15-If-the-man-applied-a-horizontal-force-200N-and-the-box-moves-up-the-plane-a-distance-of-20m-at-a-constant-velocity-and-the-coefficient-of-friction-is-0-

Question Number 25308 by NECx last updated on 08/Dec/17

A m a n p u s h e s a b o x o f 40 k g u p a n

i n c l i n e o f 15 ° . I f t h e m a n a p p l i e d

a h o r i z o n t a l f o r c e 200 N a n d t h e

b o x m o v e s u p t h e p l a n e a d i s t a n c e

o f 20 m a t a c o n s t a n t v e l o c i t y a n d

t h e c o e f f i c i e n t o f f r i c t i o n i s 0.10,

f i n d

a) w o r k d o n e b y t h e m a n o n t h e

b o x

b) w o r k d o n e a g a i n s t f r i c t i o n .

Answered by jota+ last updated on 08/Dec/17

θ = 15 F = 200 N s = 20 m

m = 40 k g μ = 0.10

F_{s} = F \cos θ - m g \sin θ - μ N .

N = m g \cos θ + F \sin θ

a) W = F_{s} s

b) W = - μ N s

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