A-man-pushes-a-box-of-40kg-up-an-incline-plane-of-15-if-the-man-applies-a-horizontal-force-of-200N-and-the-box-moves-up-the-plane-a-distance-of-20m-at-a-constant-velocity-and-the-coefficient-of-frict

Question Number 28644 by NECx last updated on 28/Jan/18

A m a n p u s h e s a b o x o f 40 k g u p

a n i n c l i n e p l a n e o f 15 °, i f t h e m a n

a p p l i e s a h o r i z o n t a l f o r c e o f

200 N a n d t h e b o x m o v e s u p t h e

p l a n e a d i s t a n c e o f 20 m a t a

c o n s t a n t v e l o c i t y a n d t h e

c o e f f i c i e n t o f f r i c t i o n i s 0.10,

f i n d

a) w o r k d o n e b y t h e m a n o n t h e

b o x .

b) w o r k d o n e a g a i n s t f r i c t i o n .

Commented by NECx last updated on 29/Jan/18

p l e a s e h e l p

Commented by Tinkutara last updated on 29/Jan/18

W o r k d o n e b y m a n o n b o x = F \cos θ \times 20

= 200 \cos 15 ° \times 20 = 1000 \sqrt{2} (\sqrt{3} + 1)

f = μ N = μ (F \sin θ + m g \cos θ)

= 0.1 (200 \sin 15 ° + 40 g \cos 15 °)

Commented by Tinkutara last updated on 29/Jan/18

Commented by NECx last updated on 30/Jan/18

t h a n k y o u s o m u c h

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