A-mass-of-6kg-lies-on-an-inclined-plane-which-is-smooth-at-angle-to-the-horizontal-where-sin-1-3-if-it-is-connected-to-another-mass-8kg-by-the-same-inelastic-string-passing-over-a-smooth-fixed

Question Number 55306 by Rio Mike last updated on 21/Feb/19

A m a s s o f 6 k g l i e s o n a n i n c l i n e d p l a n e

w h i c h i s s m o o t h a t a n g l e θ t o t h e h o r i z o n t a l

w h e r e \sin θ = \frac{1}{3} . i f i t i s c o n n e c t e d t o

a n o t h e r m a s s 8 k g b y t h e s a m e i n e l a s t i c s t r i n g

p a s s i n g o v e r a s m o o t h f i x e d p u l l e y

a t t h e t o p o f t h e p l a n e . t h e p a r t i c e s a r e

r e l e a s e d f r o m r e s t, F i n d

a) t h e a c c e l e r a t i o n o f e a c h m a s s

b) t h e t e n s i o n i n t h e s t r i n g

c) t h e s p e e d o f t h e m a s s e s a f t e r 4 s e c o n d s

d) t h e d i s t a n c e d c o v e r e d w i t h t h i s t i m e

i n (c) a b o v e b y t h e m a s s e s .

2017 C G C E B p a p e r 3 M e c h a n i c s a / v

Answered by tanmay.chaudhury50@gmail.com last updated on 21/Feb/19

8 \times 10 - T = 8 a [

T - 6 \times 10 \times \frac{1}{3} = 6 a

14 a = 60 a = \frac{30}{7} m / {s e c}^{2} \to f o r b o t h m a s s

T = 80 - 8 \times \frac{30}{7} = 80 (1 - \frac{3}{7})

T = \frac{320}{7} N

v = 0 + \frac{30}{7} \times 4 = \frac{120}{7} \to f o r b o t h m a s s

s = \frac{1}{2} \times \frac{30}{7} \times 4^{2} = \frac{240}{7} m e t e r