A-mercury-based-barometer-reads-760mmhg-at-the-base-of-a-mountain-and-704-0mmhg-at-the-top-Find-the-height-of-the-mountain-if-the-density-of-mercury-and-air-are-respectively-13600kgm-3-and-1-

Question Number 123336 by Lordose last updated on 25/Nov/20

$$ \\ $$$$\mathrm{A}\:\mathrm{mercury}\:\mathrm{based}\:\mathrm{barometer}\:\mathrm{reads} \\ $$$$\mathrm{760mmhg}\:\mathrm{at}\:\mathrm{the}\:\mathrm{base}\:\mathrm{of}\:\mathrm{a}\:\mathrm{mountain}\:\mathrm{and} \\ $$$$\mathrm{704}.\mathrm{0mmhg}\:\mathrm{at}\:\mathrm{the}\:\mathrm{top}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{height}\: \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{mountain}\:\mathrm{if}\:\mathrm{the}\:\mathrm{density}\:\mathrm{of}\: \\ $$$$\mathrm{mercury}\:\mathrm{and}\:\mathrm{air}\:\mathrm{are}\:\mathrm{respectively} \\ $$$$\mathrm{13600kgm}^{−\mathrm{3}} \:\:\mathrm{and}\:\mathrm{1}.\mathrm{25kgm}^{−\mathrm{3}} \:\left(\mathrm{g}=\mathrm{10ms}^{−\mathrm{2}} \right) \\ $$

Answered by help last updated on 25/Nov/20

$$\left\{{pgh}\right\}_{\mathrm{1}} =\left\{{pgh}\right\}_{\mathrm{2}} \: \\ $$$$\mathrm{13}.\mathrm{6}\left\{\mathrm{76}−\mathrm{70}.\mathrm{4}\right\}=\mathrm{0}.\mathrm{00125}×{h} \\ $$$${h}=?? \\ $$

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