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A-motor-boat-going-downstream-overcomes-a-float-at-a-point-A-60-minutes-later-it-turns-and-after-some-time-passes-the-float-at-a-distance-of-12-km-from-the-point-A-Find-the-velocity-of-the-stream-a




Question Number 13570 by Tinkutara last updated on 21/May/17
A motor boat going downstream  overcomes a float at a point A. 60 minutes  later it turns and after some time passes  the float at a distance of 12 km from  the point A. Find the velocity of the stream  (assuming constant velocity for the  boat in still water)
AmotorboatgoingdownstreamovercomesafloatatapointA.60minuteslateritturnsandaftersometimepassesthefloatatadistanceof12kmfromthepointA.Findthevelocityofthestream(assumingconstantvelocityfortheboatinstillwater)
Answered by ajfour last updated on 21/May/17
boat moves from A for t_1 =1h  with velocity u+v.   [u=stream velocity]  it turns back, moving with speed  v−u , for time =t_2  , whereupon  it meets the float again.  the float has come down a  distance d=12km .  u(t_1 +t_2 )=d            .....(i)  (u+v)t_1 −(v−u)t_2 =d       ....(ii)  from eq. (ii)  u(t_1 +t_2 )+v(t_1 −t_2 )=d  using (i) in (ii),  t_2 =t_1 =1h  so,   u=(d/((t_1 +t_2 )))=((12km)/(2h))  u=6km/h .
boatmovesfromAfort1=1hwithvelocityu+v.[u=streamvelocity]itturnsback,movingwithspeedvu,fortime=t2,whereuponitmeetsthefloatagain.thefloathascomedownadistanced=12km.u(t1+t2)=d..(i)(u+v)t1(vu)t2=d.(ii)fromeq.(ii)u(t1+t2)+v(t1t2)=dusing(i)in(ii),t2=t1=1hso,u=d(t1+t2)=12km2hu=6km/h.
Commented by Tinkutara last updated on 21/May/17
Thanks Sir!
ThanksSir!

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