Question Number 40773 by Necxx last updated on 27/Jul/18
$${A}\:{pair}\:{of}\:{oppositely}\:{charged}\:{plane} \\ $$$${parallel}\:{plates}\:{each}\:{of}\:{area},\mathrm{100}{cm}^{\mathrm{2}} \\ $$$${has}\:{the}\:{electric}\:{field}\:{of}\:{the}\:{value} \\ $$$$\mathrm{5}.\mathrm{0}×\mathrm{10}^{\mathrm{4}} {N}/{C}.{Calculate}\:{the}\:{charge} \\ $$$${on}\:{each}\:{plate}. \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 27/Jul/18
$${E}=\frac{\sigma}{\epsilon_{\mathrm{0}} }\:\:\:\:\:{so}\:\:\sigma={E}\epsilon_{\mathrm{0}} \\ $$$${q}=\sigma{A}={E}\epsilon_{\mathrm{0}} {A} \\ $$$${q}=\mathrm{5}.\mathrm{0}×\mathrm{10}^{\mathrm{4}} ×\mathrm{8}.\mathrm{854}×\mathrm{10}^{−\mathrm{12}} ×\mathrm{100}×\mathrm{10}^{−\mathrm{4}} \\ $$$$=\mathrm{5}.\mathrm{0}×\mathrm{8}.\mathrm{854}×\mathrm{10}^{\mathrm{4}−\mathrm{12}+\mathrm{2}−\mathrm{4}} \\ $$$$=\mathrm{44}.\mathrm{27}×\mathrm{10}^{−\mathrm{10}} \:{C} \\ $$
Commented by Necxx last updated on 27/Jul/18
$${wow}.{Thanks}\:{so}\:{much} \\ $$