A-particle-is-projected-at-an-angle-60-with-speed-10-3-m-s-from-the-point-A-as-shown-in-the-figure-At-the-same-time-the-wedge-is-made-to-move-with-speed-10-3-m-s-toward-right-as-shown-in-figure-

Question Number 18265 by Tinkutara last updated on 17/Jul/17

A particle is projected at an angle 60 °

with speed 10 \sqrt{3} m / s from the point A

as shown in the figure . At the same

time the wedge is made to move with

speed 10 \sqrt{3} m / s toward right as shown

in figure . Find the time after which

particle will strike the wedge .

Commented by Tinkutara last updated on 17/Jul/17

Commented by ajfour last updated on 18/Jul/17

In order to collide at time t

10 \sqrt{3} t = ycot 30 ° + (10 \sqrt{3}) [\cos 60 °] t

10 \sqrt{3} t = y \sqrt{3} + 5 \sqrt{3} t

y = 5 t

Also y = (10 \sqrt{3}) (\frac{\sqrt{3}}{2}) t - \frac{{gt}^{2}}{2}

\Rightarrow 5 t = 15 t - {5 t}^{2}

t^{2} - 2 t = 0

t = 2 s .

Commented by ajfour last updated on 18/Jul/17

and just now .

Commented by Tinkutara last updated on 18/Jul/17

Thanks Sir!

Commented by Tinkutara last updated on 07/Mar/18

Sir I have a doubt now. Sorry for too late! But why ycot30° is used?

Commented by ajfour last updated on 08/Mar/18

t h e w e d g e h a s t o t r a v e l t h i s e x t r a

h o r i z o n t a l d i s t a n c e t o c o l l i d e w i t h

t h e p a r t i c l e i f t h e y c o l l i d e a t l e v e l

y = y .

Commented by Tinkutara last updated on 08/Mar/18

Oh yes thanks!

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