A-point-moves-in-x-y-plane-according-to-the-law-x-4-sin-6t-and-y-4-1-cos-6t-Find-distance-traversed-by-the-particle-in-5-seconds-when-x-and-y-are-in-metres-

Question Number 14939 by Tinkutara last updated on 05/Jun/17

A point moves in x - y plane according

to the law x = 4 \sin 6 t and

y = 4 (1 - \cos 6 t) . Find distance traversed

by the particle in 5 seconds, when x and

y are in metres .

Answered by ajfour last updated on 05/Jun/17

x^{2} + {(y - 4)}^{2} = 4^{2}

p a r t i c l e m o v e s i n a c i r c l e o f r a d i u s

4 m w i t h c e n t r e a s (0, 4 m) .

v = ω r = (6 r a d / s) (4 m) = 24 m / s .

d i s t a n c e t r a v e l e d i n 5 s i s

d = v t = (24 m / s) (5 s) = 120 m .

Commented by Tinkutara last updated on 05/Jun/17

Thanks Sir!