Question Number 31371 by momo last updated on 07/Mar/18
$${A}\:{point}\:{moves}\:{in}\:{xy}\:{plane}\:{such}\: \\ $$$${that}\:{sum}\:{of}\:{its}\:{distance}\:{from}\:{two}\: \\ $$$${mutually}\:{perpendicular}\:{lines}\:{is} \\ $$$${always}\:\mathrm{3}.{The}\:{area}\:{encloded}\:{by} \\ $$$${the}\:{locus}\:{of}\:{the}\:{point}\:{is} \\ $$
Answered by ajfour last updated on 07/Mar/18
$${Area}\:{enclosed}\:{by} \\ $$$$\mid{x}\mid+\mid{y}\mid=\mathrm{3}\:\:{is}\:=\:\left(\mathrm{3}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} \:=\:\mathrm{18}\:{sq}.{units}\:. \\ $$
Commented by momo last updated on 07/Mar/18
$${explain}\:{please} \\ $$