A-refrigerator-use-1200joules-of-work-to-jump-300j-of-heat-from-a-cold-reservoir-of-275k-to-a-hot-reservoir-at-320k-1-What-is-the-coefficient-of-performance-2-the-maximum-efficiency-of-performan

Question Number 179289 by Tawa11 last updated on 27/Oct/22

A refrigerator use 1200joules of work to jump 300j of heat from a cold reservoir of 275k to a hot reservoir at 320k.

1. What is the coefficient of performance.
2 the maximum efficiency of performance.

Answered by Acem last updated on 27/Oct/22

1 ∙ K = \frac{∣ Q_{c} ∣}{∣ W ∣} = \frac{300}{1200} = \frac{1}{4}

2 ∙ K_{c a r n o t} = \frac{T_{c}}{T_{H} - T_{c}} = 6.1

Commented by Tawa11 last updated on 28/Oct/22

I appreciate sir .

Commented by Acem last updated on 28/Oct/22

{Y o u}^{'} r e w e l c o m e

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