Menu Close

A-resistor-R-is-connected-in-series-with-a-parallel-combination-of-two-resistors-of-24-and-8-ohms-The-total-power-disipated-in-the-circuit-is-64-watt-when-the-applied-voltage-is-24-volt-Find-R-




Question Number 14963 by tawa tawa last updated on 06/Jun/17
A resistor R is connected in series with a parallel combination of two resistors  of 24 and 8 ohms . The total power disipated in the circuit is 64 watt when the  applied voltage is 24 volt.Find R
AresistorRisconnectedinserieswithaparallelcombinationoftworesistorsof24and8ohms.Thetotalpowerdisipatedinthecircuitis64wattwhentheappliedvoltageis24volt.FindR
Answered by ajfour last updated on 06/Jun/17
 P=(V^2 /R_(eq) ) , R_(eq) =R+((24×8)/(32))Ω =R+6Ω ;  ⇒ 64W=(((24V)^2 )/((R+6Ω)))  or,      R+6Ω=((24×24)/(64)) Ω               R = 9Ω−6Ω =3Ω  .
P=V2Req,Req=R+24×832Ω=R+6Ω;64W=(24V)2(R+6Ω)or,R+6Ω=24×2464ΩR=9Ω6Ω=3Ω.
Commented by tawa tawa last updated on 06/Jun/17
God bless you sir.
Godblessyousir.

Leave a Reply

Your email address will not be published. Required fields are marked *