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A-Satellite-orbits-the-esrth-in-a-circle-of-rsdius-8000km-At-that-distance-from-the-earth-g-6-2m-s2-The-velocity-of-the-satelliege-is-




Question Number 104143 by aurpeyz last updated on 19/Jul/20
A Satellite orbits the esrth in a circle of rsdius 8000km. At that distance from the earth g=6.2m/s2. The velocity of the satelliege is?
ASatelliteorbitstheesrthinacircleofrsdius8000km.Atthatdistancefromtheearthg=6.2m/s2.Thevelocityofthesatelliegeis?
Commented by aurpeyz last updated on 19/Jul/20
pls help
plshelp
Answered by OlafThorendsen last updated on 19/Jul/20
F^→  = mg^→  = ma_N ^→ = m(v^2 /R)u^→   ⇒ v = (√(gR)) = (√(6,2×8.10^6 ))  v = 7,042 km/s
F=mg=maN=mv2Ruv=gR=6,2×8.106v=7,042km/s
Commented by aurpeyz last updated on 20/Jul/20
thnks
thnks
Commented by aurpeyz last updated on 01/Aug/20
pls how did you get R as 8.10^6 ?
plshowdidyougetRas8.106?

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