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Question Number 32312 by NECx last updated on 23/Mar/18
A small ball is dropped from a   height of 1m into a horizontal  floor.Each time it rebounces to  3/5 of the height it has fallen.  a)show that when the ball strikes  the ground for the third time ,it  has travelled a distance of 2.92m  b)Show that the total distance  travelled by the ball cant exceed  4m.
Asmallballisdroppedfromaheightof1mintoahorizontalfloor.Eachtimeitrebouncesto3/5oftheheightithasfallen.a)showthatwhentheballstrikesthegroundforthethirdtime,ithastravelledadistanceof2.92mb)Showthatthetotaldistancetravelledbytheballcantexceed4m.
Commented by NECx last updated on 23/Mar/18
please help with this
pleasehelpwiththis
Answered by mrW2 last updated on 23/Mar/18
1st strike: l_1 =1  2nd strike: l_2 =1+(3/5)×2  3rd strike: l_3 =1+(3/5)×2+((3/5))^2 ×2=2.92m  ....  n−th strike: l_n =1+(3/5)×2+((3/5))^2 ×2+...+((3/5))^(n−1) ×2  l_n =2[1+(3/5)+((3/5))^2 +...+((3/5))^(n−1) ]−1  lim_(n→∞)  l_n =(2/(1−(3/5)))−1=4 m  ⇒l_n <4 m
1ststrike:l1=12ndstrike:l2=1+35×23rdstrike:l3=1+35×2+(35)2×2=2.92m.nthstrike:ln=1+35×2+(35)2×2++(35)n1×2ln=2[1+35+(35)2++(35)n1]1limnln=21351=4mln<4m
Commented by NECx last updated on 25/Mar/18
wow..... Thanks
wow..Thanks
Commented by NECx last updated on 25/Mar/18
If I may ask,what does the ×2  represents. Since the object reboundes  (3/5) of the actual height I thought  it would have been   l_2 =1+((3/5))×2    please explain.Thanks
IfImayask,whatdoesthe×2represents.Sincetheobjectreboundes35oftheactualheightIthoughtitwouldhavebeenl2=1+(35)×2pleaseexplain.Thanks
Commented by mrW2 last updated on 06/Apr/18
you are right sir. it is also that what  I wrote:  l_2 =1+((3/5))×2  l_3 =1+((3/5))×2+((3/5))^2 ×2  ......  l_n =1+((3/5))×2+((3/5))^2 ×2+...+((3/5))^(n−1) ×2
youarerightsir.itisalsothatwhatIwrote:l2=1+(35)×2l3=1+(35)×2+(35)2×2ln=1+(35)×2+(35)2×2++(35)n1×2

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