Question Number 32312 by NECx last updated on 23/Mar/18

Commented by NECx last updated on 23/Mar/18

Answered by mrW2 last updated on 23/Mar/18
![1st strike: l_1 =1 2nd strike: l_2 =1+(3/5)×2 3rd strike: l_3 =1+(3/5)×2+((3/5))^2 ×2=2.92m .... n−th strike: l_n =1+(3/5)×2+((3/5))^2 ×2+...+((3/5))^(n−1) ×2 l_n =2[1+(3/5)+((3/5))^2 +...+((3/5))^(n−1) ]−1 lim_(n→∞) l_n =(2/(1−(3/5)))−1=4 m ⇒l_n <4 m](https://www.tinkutara.com/question/Q32370.png)
Commented by NECx last updated on 25/Mar/18

Commented by NECx last updated on 25/Mar/18

Commented by mrW2 last updated on 06/Apr/18
