Question Number 35088 by Raj Singh last updated on 15/May/18
$$\boldsymbol{{a}}\:\boldsymbol{{son}}\:\boldsymbol{{and}}\:\boldsymbol{{father}}\:\boldsymbol{{do}}\:\boldsymbol{{a}}\:\boldsymbol{{work}}\:\boldsymbol{{in}} \\ $$$$\mathrm{24}\:\boldsymbol{{day}}\:.\:\boldsymbol{{if}}\:\boldsymbol{{both}}\:\boldsymbol{{work}}\:\boldsymbol{{together}} \\ $$$$\boldsymbol{{and}}\:\boldsymbol{{father}}\:\boldsymbol{{work}}\:\boldsymbol{{last}}\:\mathrm{6}\:\boldsymbol{{day}}\:\boldsymbol{{only}} \\ $$$$\boldsymbol{{then}}\:\boldsymbol{{they}}\:\boldsymbol{{how}}\:\boldsymbol{{much}}\:\boldsymbol{{do}} \\ $$
Commented by Rasheed.Sindhi last updated on 15/May/18
$$\mathrm{Data}\:\mathrm{seems}\:\mathrm{incomplete}. \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 15/May/18
$${let}\:{father}\:{do}\:\frac{\mathrm{1}}{{f}}\:{portion}\:{in}\:{a}\:{day} \\ $$$${son}\:{do}\:\frac{\mathrm{1}}{{s}\:}{portion}\:{in}\:{a}\:{day} \\ $$$${so}\:\mathrm{24}\left(\frac{\mathrm{1}}{{f}}+\frac{\mathrm{1}}{{s}}\right)=\mathrm{1} \\ $$$$\frac{\mathrm{1}}{{f}}+\frac{\mathrm{1}}{{s}}=\frac{\mathrm{1}}{\mathrm{24}} \\ $$$${in}\:{last}\:\mathrm{6}\:{day}\:{father}\:{do}\:\frac{\mathrm{6}}{{f}}\:{portion} \\ $$$${remaining}\:{work}\:\left(\mathrm{1}−\frac{\mathrm{6}}{{f}}\right) \\ $$$$\frac{\mathrm{6}}{{f}}+\frac{\mathrm{6}}{{s}}=\frac{\mathrm{6}}{\mathrm{24}} \\ $$$$\frac{\mathrm{6}}{{f}}=\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{6}}{{s}} \\ $$$${remaining}\:{work}\:=\left(\mathrm{1}−\frac{\mathrm{6}}{{f}}\right) \\ $$$$=\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{6}}{{s}}\right) \\ $$$$=\frac{\mathrm{3}}{\mathrm{4}}+\frac{\mathrm{6}}{{s}} \\ $$$${so}\:{remaining}\:{work}>\frac{\mathrm{3}}{\mathrm{4}} \\ $$