Question Number 15294 by arnabpapu550@gmail.com last updated on 09/Jun/17
$$\mathrm{A}\:\mathrm{straigth}\:\mathrm{conductor}\:\mathrm{of}\:\mathrm{length} \\ $$$$\mathrm{L}\:\mathrm{is}\:\mathrm{charged}\:\mathrm{with}\:\mathrm{q}\:\mathrm{charge}.\:\mathrm{What} \\ $$$$\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{electric}\:\mathrm{field}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{equatorial}\:\mathrm{line}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{d}\:? \\ $$$$\mathrm{Ans}:\:\frac{\mathrm{2q}}{\mathrm{4}\Pi\epsilon_{\mathrm{0}} \mathrm{d}\sqrt{\mathrm{L}^{\mathrm{2}} +\mathrm{4d}^{\mathrm{2}} }} \\ $$
Commented by arnabpapu550@gmail.com last updated on 09/Jun/17
