A-string-of-negligible-mass-going-over-a-clamped-pulley-of-mass-m-supports-a-block-of-mass-M-The-force-on-the-pulley-by-the-clamp-is-given-by-

Question Number 22319 by Tinkutara last updated on 15/Oct/17

A string of negligible mass going over a

clamped pulley of mass m supports a

block of mass M . The force on the

pulley by the clamp is given by

Commented by Tinkutara last updated on 15/Oct/17

Commented by mrW1 last updated on 15/Oct/17

F_{x} = Mg

F_{y} = (M + m) g

F = \sqrt{M^{2} + {(M + m)}^{2}} g

= \sqrt{2 M (M + m) + m^{2}} g

Commented by Tinkutara last updated on 15/Oct/17

B u t a n s w e r i s [\sqrt{{(M + m)}^{2} + m^{2}}] g

Commented by ajfour last updated on 15/Oct/17

I f m = 0, w h i c h a n s w e r a g r e e s ?

Commented by mrW1 last updated on 15/Oct/17

If M = 0, the force should be mg .

If m = 0, the force should be \sqrt{2} Mg .

Commented by mrW1 last updated on 16/Oct/17

Commented by ajfour last updated on 16/Oct/17

y e s s i r, g o o d a g r e e m e n t .

Commented by Tinkutara last updated on 18/Oct/17

Thank you very much Sir!

Answered by math solver last updated on 16/Oct/17

a n s w e r b y m r w 1 i s a b s o l u t e l y c o r r e c t!

P . S : i t i s a n o l d j e e p r o b l e m