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A-triangle-ABC-has-the-following-properties-BC-1-AB-BC-and-that-the-angle-bisector-from-vertex-B-is-also-a-median-Find-all-possible-triangle-s-with-its-their-side-lengths-and-angles-




Question Number 112209 by Aina Samuel Temidayo last updated on 06/Sep/20
A triangle ABC has the following  properties BC=1, AB=BC and that  the angle bisector from vertex B is  also a median. Find all possible  triangle(s) with its/their  side−lengths and angles.
AtriangleABChasthefollowingpropertiesBC=1,AB=BCandthattheanglebisectorfromvertexBisalsoamedian.Findallpossibletriangle(s)withits/theirsidelengthsandangles.
Commented by Aina Samuel Temidayo last updated on 07/Sep/20
It should be  AB=AC and not  AB=BC please. Can you try solving  now?
ItshouldbeAB=ACandnotAB=BCplease.Canyoutrysolvingnow?
Commented by Aina Samuel Temidayo last updated on 07/Sep/20
Hello. I think that question is  incorrect.
Hello.Ithinkthatquestionisincorrect.
Commented by 1549442205PVT last updated on 07/Sep/20
Triangle ABC is isosceles at B then  the bisector of the angle ABC^(�)  is  always its median,so this hypothesis  isn′t necessary.It is unnecessary
TriangleABCisisoscelesatBthenthebisectoroftheangleABC^isalwaysitsmedian,sothishypothesisisntnecessary.Itisunnecessary
Commented by Aina Samuel Temidayo last updated on 07/Sep/20
Your solution please?
Yoursolutionplease?
Commented by 1549442205PVT last updated on 07/Sep/20
This is always true for ∀B^(�) .The  property of two amgles having their  sum equal to 90°:If α+β=90° then  sinα=cosβ,cosα=sinα,tanα=cotβ  .On the other words,  sinα=cos(90°−α)....cosα=sin(90°−α)
ThisisalwaystrueforB^.Thepropertyoftwoamgleshavingtheirsumequalto90°:Ifα+β=90°thensinα=cosβ,cosα=sinα,tanα=cotβ.Ontheotherwords,sinα=cos(90°α).cosα=sin(90°α)
Commented by 1549442205PVT last updated on 07/Sep/20
Ok
Ok

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