Question Number 23666 by Tinkutara last updated on 03/Nov/17

Commented by Tinkutara last updated on 03/Nov/17

Answered by ajfour last updated on 03/Nov/17

Answered by ajfour last updated on 03/Nov/17

Commented by ajfour last updated on 04/Nov/17
![mg−F=(dp/dt) =(d/dt)[(m/l)(((l−x)/2))v] =(m/(2l))(d/dt)[(l−x)v] =(m/(2l))[−v^2 +(l−x)g]=(m/(2l))[−2gx−gx+gl] ⇒ F= mg+(m/(2l))(3gx−gl) =((mg)/2)(1+((3x)/l)) F =((𝛌lg)/2)(1+((3x)/l)) .](https://www.tinkutara.com/question/Q23681.png)
Commented by Tinkutara last updated on 04/Nov/17
