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A-wave-has-a-wavelength-of-1-5m-calculate-the-phase-angle-between-a-point-0-25m-from-the-peak-of-the-wave-and-another-point-1m-further-along-the-same-peak-




Question Number 38924 by NECx last updated on 01/Jul/18
A wave has a wavelength of 1.5m,  calculate the phase angle between  a point 0.25m from the peak of the  wave and another point 1m further  along the same peak.
Awavehasawavelengthof1.5m,calculatethephaseanglebetweenapoint0.25mfromthepeakofthewaveandanotherpoint1mfurtheralongthesamepeak.
Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18
φ_1 =((2Πx)/λ)=((2Π×0.25)/(1.5))=((2Π×25×10)/(100×15))=(Π/3)  ∅_2 =((2Πx)/λ)=((2Π×1)/(1.5))=((4Π)/3)  △φ=((4Π)/3)−(Π/3)=Π
ϕ1=2Πxλ=2Π×0.251.5=2Π×25×10100×15=Π32=2Πxλ=2Π×11.5=4Π3ϕ=4Π3Π3=Π

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