A-wave-has-a-wavelength-of-1-5m-calculate-the-phase-angle-between-a-point-0-25m-from-the-peak-of-the-wave-and-another-point-1m-further-along-the-same-peak-

Question Number 38924 by NECx last updated on 01/Jul/18

A w a v e h a s a w a v e l e n g t h o f 1.5 m,

c a l c u l a t e t h e p h a s e a n g l e b e t w e e n

a p o i n t 0.25 m f r o m t h e p e a k o f t h e

w a v e a n d a n o t h e r p o i n t 1 m f u r t h e r

a l o n g t h e s a m e p e a k .

Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18

ϕ_{1} = \frac{2 Π x}{λ} = \frac{2 Π \times 0.25}{1.5} = \frac{2 Π \times 25 \times 10}{100 \times 15} = \frac{Π}{3}

\emptyset_{2} = \frac{2 Π x}{λ} = \frac{2 Π \times 1}{1.5} = \frac{4 Π}{3}

△ ϕ = \frac{4 Π}{3} - \frac{Π}{3} = Π