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A-wave-of-frequency-10hz-forms-a-stationery-wave-pattern-in-a-medium-where-the-velocity-is-20cms-1-what-is-the-distance-between-the-adjacent-nodes-pls-help-




Question Number 30861 by Victor31926 last updated on 27/Feb/18
A wave of frequency 10hz forms  a stationery wave pattern in a medium  where the velocity is 20cms^(−1)   what is the distance between the adjacent nodes?    pls help..
$$\mathrm{A}\:\mathrm{wave}\:\mathrm{of}\:\mathrm{frequency}\:\mathrm{10hz}\:\mathrm{forms} \\ $$$$\mathrm{a}\:\mathrm{stationery}\:\mathrm{wave}\:\mathrm{pattern}\:\mathrm{in}\:\mathrm{a}\:\mathrm{medium} \\ $$$$\mathrm{where}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{is}\:\mathrm{20cms}^{−\mathrm{1}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{the}\:\mathrm{adjacent}\:\mathrm{nodes}? \\ $$$$ \\ $$$$\mathrm{pls}\:\mathrm{help}.. \\ $$
Answered by 803jaideep@gmail.com last updated on 01/Mar/18
lemda=(20/100)/10=1/50  adjacent nodes distance is half of  1/50... so 1/100
$$\mathrm{lemda}=\left(\mathrm{20}/\mathrm{100}\right)/\mathrm{10}=\mathrm{1}/\mathrm{50} \\ $$$$\mathrm{adjacent}\:\mathrm{nodes}\:\mathrm{distance}\:\mathrm{is}\:\mathrm{half}\:\mathrm{of} \\ $$$$\mathrm{1}/\mathrm{50}…\:\mathrm{so}\:\mathrm{1}/\mathrm{100} \\ $$

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