A-whatsapp-group-contains-7-women-and-3-men-If-they-are-leaving-the-group-one-at-a-time-from-the-group-what-is-the-probability-of-a-woman-leaving-then-a-man-leaving-and-so-on-alternately-until-only-a-

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Question Number 55344 by Necxx last updated on 21/Feb/19

$$Awhatsappgroupcontains7women$$$$and3men.Iftheyareleaving$$$$thegrouponeatatimefromthe$$$$groupwhatistheprobabilityofa$$$$womanleavingthenamanleaving$$$$andsoonalternatelyuntilonlya$$$$womanisremaining?$$$$$$

Commented by mr W last updated on 22/Feb/19

$$WMWMWMWWWW\to leaving$$$$\frac{7\times 3\times 6\times 2\times 5\times 1\times 4!}{10!}$$$$=\frac{3\times 2}{10\times 9\times 8}$$$$=\frac{1}{120}$$

Commented by necx1 last updated on 23/Feb/19

$$yeah\dots .Thanks$$

Commented by rahul 19 last updated on 23/Feb/19

$$Sir,plexplainmorewhatyouhavedone.$$

Commented by mr W last updated on 24/Feb/19

$$totalnumberofwaystoarrange10$$$$personsis10!.$$$$suchthatthepersonsleavewhatsapp$$$$inthewayasrequestedinthequestion,$$$$thepersonsshouldbearrangedlike$$$$this:$$$$WMWMWMWWWW\to leavingwhatsapp$$$$withW=woman,M=man$$$$thereare7!3!sucharrangements,$$$$thereforetheprobabilityis$$$$\frac{7!3!}{10!}=\frac{3!}{10\times 9\times 8}=\frac{1}{120}$$

Commented by rahul 19 last updated on 25/Feb/19

$$thankUsir!$$

Commented by rahul 19 last updated on 25/Feb/19

Today is 25th Feb'19 ... why my comment shows 24th Feb'19 ? some technical error ...

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