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a-word-is-formed-with-3-vowels-and-3-consonants-without-repetition-the-probability-the-formation-of-words-begining-the-letter-z-is-




Question Number 82111 by john santu last updated on 18/Feb/20
a word is formed with 3 vowels  and 3 consonants without   repetition . the probability the  formation of words begining the  letter z is?
awordisformedwith3vowelsand3consonantswithoutrepetition.theprobabilitytheformationofwordsbeginingtheletterzis?
Commented by john santu last updated on 18/Feb/20
i′ got answer p = (C_2 ^(20) /(6×C_3 ^( 21) ))
igotanswerp=C2206×C321
Commented by mr W last updated on 18/Feb/20
p=((C_2 ^(20) C_3 ^5 5!)/(C_3 ^(21) C_3 ^5 6!))=(C_2 ^(20) /(6C_3 ^(21) ))=(1/(42))
p=C220C355!C321C356!=C2206C321=142
Commented by jagoll last updated on 18/Feb/20
n(S) = 6! C _3^(21) .C_3 ^5   n(A) = 5! C_2 ^(20) .C_3 ^5   p(A) = ((5! C_2 ^(21) .C_3 ^5 )/(6! C_3 ^(21) .C_3 ^5 )) = (C_2 ^(21) /(6.C_3 ^(21) ))
n(S)=6!C321.C35n(A)=5!C220.C35p(A)=5!C221.C356!C321.C35=C2216.C321
Commented by mr W last updated on 18/Feb/20
6 is correct sir!
6iscorrectsir!
Commented by jagoll last updated on 18/Feb/20
thank you sir
thankyousir
Commented by john santu last updated on 18/Feb/20
thank you. i wrote it wrong  because  in a hurry
thankyou.iwroteitwrongbecauseinahurry

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