A-x-2ax-2-1-3-2a-2a-2-x-1-3-1-1-x-1-3-2a-1-3-2a-1-3-6-a-b-R-2-a-A-16a-4-x-2-b-A-8-ax-c-A-2a-1-3-3x

Question Number 146764 by Ar Brandon last updated on 15/Jul/21

A = {(\frac{(x + \sqrt[3]{{2 ax}^{2}}) {(2 a + \sqrt[3]{{2 a}^{2} x})}^{- 1} - 1}{\sqrt[3]{x} - \sqrt[3]{2 a}} - {(2 a)}^{- 1 / 3})}^{- 6}, (a, b) \in R^{2}

a - A = \frac{{16 a}^{4}}{x^{2}} b - A = \frac{8}{ax} c - A = \frac{\sqrt[3]{2 a}}{{3 x}^{3}}