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Question Number 180938 by Shrinava last updated on 19/Nov/22
ab^(−) + ba^(−) = c3^(−) find: a+b+2c=?
ab―+ba―=c3―find:a+b+2c=?
Answered by Rasheed.Sindhi last updated on 19/Nov/22
ab^(−) + ba^(−) = c3^(−) ; a+b+2c=? 10a+b+10b+a=10c+3 11a+11b=10c+3 a+b=((10c+3)/(11)) ∈N ∧ 0≤c≤9 ⇒ c=3 a+b+2c=((10(3)+3)/(11))+2(3)=9
ab―+ba―=c3―;a+b+2c=?10a+b+10b+a=10c+311a+11b=10c+3a+b=10c+311∈N∧0⩽c⩽9⇒c=3a+b+2c=10(3)+311+2(3)=9
Answered by manxsol last updated on 19/Nov/22
ab + ((ba)/(c3)) a,b≠0 a+b⟨10 posibilitaes determinant ((a,b,c),(1,2,3),(2,1,3)) (a,b,c)=(1,2,3} (a,b,c)=(2,1,3) a+b+2c=9
ab+bac3a,b≠0a+b⟨10posibilitaesabc123213(a,b,c)=(1,2,3}(a,b,c)=(2,1,3)a+b+2c=9

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