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ABC-AB-a-BC-b-AC-c-and-C-90-r-




Question Number 84304 by Wepa last updated on 11/Mar/20
ΔABC AB=a BC=b AC=c   and ∠C=90°  r=?
ΔABCAB=aBC=bAC=candC=90°r=?
Commented by mr W last updated on 11/Mar/20
r=((ab)/(a+b+c))
r=aba+b+c
Answered by $@ty@m123 last updated on 11/Mar/20
General formula:  r=(△/s), △=(1/2)absin C  Here C=90^o   ∴ r=((absin 90^o )/(2×((a+b+c)/2)))  ⇒ r=((ab)/(a+b+c))
Generalformula:r=s,=12absinCHereC=90or=absin90o2×a+b+c2r=aba+b+c

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