According-to-relativistic-theory-E-2-p-2-c-2-m-0-2-c-4-where-m-0-is-rest-mass-For-photon-E-pc-m-0-0-for-photon-For-electron-E-mc-2-Unlike-photon-Why-p-2-c-2-is-neglected-in-case

FacebookTweetPin

Question Number 45646 by rahul 19 last updated on 15/Oct/18

$$Accordingtorelativistictheory,$$$$E^2=p^2{c}^2+m_0^2{c}^{4}where{m}_{0}isrestmass.$$$$ForphotonE=pc\dots$$$$(m_0=0forphoton)$$$$ForelectronE={mc}^2\dots$$$$Unlikephoton,Why{p}^2{c}^{2}isneglected$$$$incaseofelectron?$$

Commented by hassentimol last updated on 15/Oct/18

$$$$$$$$$$\mathrm{For}\mathrm{photons},\mathrm{the}\mathrm{mass}\mathrm{is}\mathrm{equal}\mathrm{to}0.$$$$\mathrm{So},0^2\times {\mathrm{c}}^2=0,\mathrm{so}\mathrm{this}\mathrm{part}\mathrm{is}\mathrm{neglected}\mathrm{for}\mathrm{that}\mathrm{reason}.$$$$$$$$\mathrm{The}\mathrm{mass}\mathrm{of}\mathrm{an}\mathrm{electron},\mathrm{is}\mathrm{not}\mathrm{null}\mathrm{indeed},$$$$\mathrm{however},\mathrm{as}\mathrm{it}\mathrm{is}\mathrm{a}\mathrm{very}\mathrm{small}\mathrm{number},$$$$\mathrm{the}\mathrm{number}\mathrm{become}\mathrm{smaller}\mathrm{while}\mathrm{being}$$$$\mathrm{squared}\mathrm{thought}\mathrm{it}\mathrm{is}\mathrm{multiplied}\mathrm{by}\mathrm{the}\mathrm{square}$$$$\mathrm{of}\mathrm{the}\mathrm{celerity}.$$$${\mathrm{That}}^{\prime }\mathrm{s}\mathrm{why}\mathrm{it}\mathrm{is}\mathrm{neglected}\mathrm{and}\mathrm{must}\mathrm{be}\mathrm{an}$$$$\mathrm{aproximate}\mathrm{answer}\mathrm{and}\mathrm{not}\mathrm{an}\mathrm{exact}\mathrm{one}.$$

Commented by rahul 19 last updated on 15/Oct/18

$$thankssir.$$

Terms of Service
Privacy Policy
Contact: info@tinkutara.com

FacebookTweetPin