advanced-calculus-calculate-0-pi-pi-1-sin-x-cos-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 123020 by mnjuly1970 last updated on 21/Nov/20 …advancedcalculus..calculate::∅=∫0ππ1−sin(x)cos(x)dx=???……………….. Answered by Dwaipayan Shikari last updated on 21/Nov/20 ∫0ππ1−12sin2xdx=2∫0∞2π2−2t1+t2.11+t2dtt=tanx=2∫0∞πt2−t+1dt=2∫0∞π(t−12)+(34)2=[4π3tan−12t−13]0∞=2π23 Commented by mnjuly1970 last updated on 21/Nov/20 thankyousomuch… Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-123018Next Next post: let-f-x-ln-1-x-2-x-2-1-calculate-f-n-x-2-calculate-f-n-0-3-developp-f-x-at-integr-serie- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.