Question Number 65189 by arcana last updated on 26/Jul/19
$${all}\:{square}\:{is}\:{a}\:{rhombus}.\:{why}? \\ $$
Answered by MJS last updated on 26/Jul/19
$$\mathrm{a}\:\mathrm{rhombus}\:\mathrm{has}\:\mathrm{2}\:\mathrm{parallel}\:\mathrm{pairs}\:\mathrm{of}\:\mathrm{sides},\:\mathrm{all} \\ $$$$\mathrm{of}\:\mathrm{them}\:\mathrm{of}\:\mathrm{equal}\:\mathrm{length} \\ $$$$\mathrm{a}\:\mathrm{square}\:\mathrm{is}\:\mathrm{a}\:\mathrm{special}\:\mathrm{kind}\:\mathrm{of}\:\mathrm{rhombus} \\ $$