Question Number 23429 by gopikrishnan005@gmail.com last updated on 30/Oct/17
$${An}\:{asymptote}\:{to}\:{the}\:{curve}\:{y}^{\mathrm{2}} \left(\mathrm{1}+{x}\right)={x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right)\:{is} \\ $$
Commented by FilupES last updated on 31/Oct/17
$${y}^{\mathrm{2}} =\frac{{x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right)}{\left(\mathrm{1}+{x}\right)} \\ $$$$\mathrm{asymptote}\:\mathrm{when}: \\ $$$$\mathrm{1}+{x}=\mathrm{0}\:\Rightarrow\:{x}=\mathrm{1} \\ $$