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An-element-X-has-RAM-of-88g-when-a-current-of-0-5A-was-passed-through-fused-chloride-of-X-for-32minutes-and-10sec-0-44g-of-X-was-deposited-at-the-cathode-a-number-of-faraday-b-write-formular-of-X




Question Number 62750 by peter frank last updated on 24/Jun/19
An element X has RAM  of 88g.when a current  of 0.5A was passed through  fused chloride of X for  32minutes and 10sec.  0.44g of X was deposited  at the cathode  (a)number of faraday?  (b)write formular of   X ions  (c)write the formular of OH
$${An}\:{element}\:{X}\:{has}\:{RAM} \\ $$$${of}\:\mathrm{88}{g}.{when}\:{a}\:{current} \\ $$$${of}\:\mathrm{0}.\mathrm{5}{A}\:{was}\:{passed}\:{through} \\ $$$${fused}\:{chloride}\:{of}\:{X}\:{for} \\ $$$$\mathrm{32}{minutes}\:{and}\:\mathrm{10}{sec}. \\ $$$$\mathrm{0}.\mathrm{44}{g}\:{of}\:{X}\:{was}\:{deposited} \\ $$$${at}\:{the}\:{cathode} \\ $$$$\left({a}\right){number}\:{of}\:{faraday}? \\ $$$$\left({b}\right){write}\:{formular}\:{of}\: \\ $$$${X}\:{ions} \\ $$$$\left({c}\right){write}\:{the}\:{formular}\:{of}\:{OH} \\ $$
Commented by peter frank last updated on 25/Jun/19
t=32min+10=1930  I=0.5  Q=I ×t  Q=0.5×1930=965  0.44g→965  88g →Q  Q=193000C  1F=96500C  x=193000  a)x=2F  (b)X^(2+)   (c)X+OH=X(OH)_2   ......
$${t}=\mathrm{32}{min}+\mathrm{10}=\mathrm{1930} \\ $$$${I}=\mathrm{0}.\mathrm{5} \\ $$$${Q}={I}\:×{t} \\ $$$${Q}=\mathrm{0}.\mathrm{5}×\mathrm{1930}=\mathrm{965} \\ $$$$\mathrm{0}.\mathrm{44}{g}\rightarrow\mathrm{965} \\ $$$$\mathrm{88}{g}\:\rightarrow{Q} \\ $$$${Q}=\mathrm{193000}{C} \\ $$$$\mathrm{1}{F}=\mathrm{96500}{C} \\ $$$${x}=\mathrm{193000} \\ $$$$\left.{a}\right){x}=\mathrm{2}{F} \\ $$$$\left({b}\right){X}^{\mathrm{2}+} \\ $$$$\left({c}\right){X}+{OH}={X}\left({OH}\right)_{\mathrm{2}} \\ $$$$…… \\ $$

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