An-object-starts-from-rest-with-constant-acceleration-4-m-s-2-then-find-the-distance-travelled-by-object-in-5-th-half-second-

Question Number 13475 by Tinkutara last updated on 20/May/17

An object starts from rest with constant

acceleration 4 m / s^{2}, then find the distance

travelled by object in 5^{th} half second .

Answered by ajfour last updated on 20/May/17

s = \frac{1}{2} {a t}^{2} w i t h u = 0

5^{t h} h a l f s e c o n d i s f r o m

t = 2 s \to t = \frac{5}{2} s

s_{2} = \frac{1}{2} (4) (4) = 8 m

s_{5 / 2} = \frac{1}{2} (4) (\frac{25}{4}) = 12.5 m

s_{5 / 2} - s_{2} = (12.5 - 8) m = 4.5 m .

Commented by Tinkutara last updated on 20/May/17

Thanks!