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An-open-flask-contains-air-at-27-C-To-what-temperature-it-must-be-heated-to-expel-one-fourth-of-the-air-




Question Number 16079 by Tinkutara last updated on 17/Jun/17
An open flask contains air at 27°C. To  what temperature it must be heated to  expel one-fourth of the air?
Anopenflaskcontainsairat27°C.Towhattemperatureitmustbeheatedtoexpelonefourthoftheair?
Commented by ajfour last updated on 18/Jun/17
is it 127°C ?  nR△T+(△n)RT =P△V+V△P   n△T+T△n =0   △T =((−T(△n))/n)           = −T(−(1/4)) =(T/4)   T−T_0 = (T_0 /4)     ⇒  T= 1.25T_0    but what is normal temperature   T= 25°   or  T=0°  ?
isit127°C?nRT+(n)RT=PV+VPnT+Tn=0T=T(n)n=T(14)=T4TT0=T04T=1.25T0butwhatisnormaltemperatureT=25°orT=0°?
Answered by mrW1 last updated on 18/Jun/17
T_2 /T_1 =V_2 /V_1 =1.25  T_2 =1.25T_1   t_2 =T_2 −273=1.25(27+273)−273=102°C
T2/T1=V2/V1=1.25T2=1.25T1t2=T2273=1.25(27+273)273=102°C

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