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Question Number 26023 by abdo imad last updated on 17/Dec/17
answer to question25980 key of slution we develop  the  foction f(x) = sin(px) at fourier serie((f 2π periodic)  f(x)= Σ_(n=1) ^(n=∝)  a_n sin(nx) and  a_n = 2/T ∫_([T]) sin(px)sin(nx)dx   (T=2π)        a_n =2π^(−1)  ∫_0 ^π sin(px)sin(nx)dx−>a_n = (−1)^n  sin(pπ).2n π^(−1) (n^2  − p^2 )^(−1)   −−>sin(px)= 2 sin(pπ).π^(−1)  Σ_(n=1) ^∝  n(−1)^(n−1) (n^2 −p^2 )^(−1)   sin(nx)  = 2π^(−1)  sin(pπ)((1^2 −p^2 )^(−1)  sin (x) −2(2^2 −p^2 )^(−1) sin(2x)+...)
answertoquestion25980keyofslutionwedevelopthefoctionf(x)=sin(px)atfourierserie((f2πperiodic)f(x)=n=1n=∝ansin(nx)andan=2/T[T]sin(px)sin(nx)dx(T=2π)an=2π10πsin(px)sin(nx)dx>an=(1)nsin(pπ).2nπ1(n2p2)1>sin(px)=2sin(pπ).π1n=1n(1)n1(n2p2)1sin(nx)=2π1sin(pπ)((12p2)1sin(x)2(22p2)1sin(2x)+)

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