Question Number 159030 by cortano last updated on 12/Nov/21
$$\:\left(\mathrm{arcsin}\:\left(\mathrm{cos}\:\mathrm{93}°\right)\right)^{\mathrm{2}} =? \\ $$
Answered by mr W last updated on 12/Nov/21
$$\mathrm{cos}\:\mathrm{93}°=−\mathrm{sin}\:\mathrm{3}°=−\mathrm{sin}\:\left(\frac{\pi}{\mathrm{60}}\right) \\ $$$${arcsin}\left(\mathrm{cos}\:\mathrm{93}°\right)={arcsin}\left(−\mathrm{sin}\:\frac{\pi}{\mathrm{60}}\right)=−\frac{\pi}{\mathrm{60}} \\ $$$$\left({arcsin}\left(\mathrm{cos}\:\mathrm{93}°\right)\right)^{\mathrm{2}} =\left(−\frac{\pi}{\mathrm{60}}\right)^{\mathrm{2}} =\frac{\pi^{\mathrm{2}} }{\mathrm{3600}} \\ $$