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arcsin-x-2-dx-




Question Number 127110 by benjo_mathlover last updated on 26/Dec/20
  ∫ (arcsin x)^2  dx =?
(arcsinx)2dx=?
Answered by liberty last updated on 27/Dec/20
 letting arcsin x = ℓ ⇒x = sin ℓ ∧ dx = cos ℓ dℓ  I= ∫ ℓ^2 cos ℓ dℓ = ℓ^2 sin ℓ +2ℓ cos ℓ−2sin ℓ + c   = x (arcsin x)^2 +2(√(1−x^2 )) arcsin x −2x + c
lettingarcsinx=x=sindx=cosdI=2cosd=2sin+2cos2sin+c=x(arcsinx)2+21x2arcsinx2x+c

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