Question Number 180157 by Tawa11 last updated on 08/Nov/22

As the force on a string increases from 100N to 180N, the string extends by 10cm. The work done in increasing the tension in the string is?
Answered by DvMc last updated on 08/Nov/22

Answered by mr W last updated on 08/Nov/22
![W=∫Fds=((100+180)/2)×0.1=14 J or k=((180−100)/(0.1))=800 N/m W=E_2 −E_1 =((k(s_2 ^2 −s_1 ^2 ))/2) =(k/2)[((F_2 /k))^2 −((F_1 /k))^2 ]=((F_2 ^2 −F_1 ^2 )/(2k)) =((180^2 −100^2 )/(2×800))=14 J](https://www.tinkutara.com/question/Q180167.png)
Commented by Tawa11 last updated on 08/Nov/22
