Question Number 23274 by Tinkutara last updated on 28/Oct/17
$$\boldsymbol{\mathrm{Assertion}}:\:\mathrm{Both}\:\mathrm{N}_{\mathrm{2}} \:\mathrm{and}\:\mathrm{NO}^{+} \:\mathrm{are} \\ $$$$\mathrm{diamagnetic}\:\mathrm{substances}. \\ $$$$\boldsymbol{\mathrm{Reason}}:\:\mathrm{NO}^{+} \:\mathrm{is}\:\mathrm{isoelectronic}\:\mathrm{with}\:\mathrm{N}_{\mathrm{2}} . \\ $$
Commented by math solver last updated on 28/Oct/17
$$\mathrm{both}\:\mathrm{statement}\:\mathrm{are}\:\mathrm{true}\:. \\ $$$$\mathrm{for}\:\mathrm{diamagnetic}\:,\:\mathrm{draw}\:\mathrm{molecular} \\ $$$$\mathrm{diagram}.\:\mathrm{and}\:\mathrm{both}\:\mathrm{have}\:\mathrm{14}\:\mathrm{electrons}. \\ $$
Commented by Tinkutara last updated on 28/Oct/17
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$