ax-2-bx-c-0-x-b-b-2-4ac-2a-Example-Find-the-values-of-x-in-the-equation-x-2-5x-4-0-In-order-to-solve-for-that-let-s-first-take-a-look-on-what-are-the-values-of-a-

Question Number 175353 by Eulerian last updated on 28/Aug/22

{ax}^{2} + bx + c = 0

x = \frac{- b \pm \sqrt{b^{2} - 4 ac}}{2 a}

Example :

Find the values of x in the equation

x^{2} + 5 x + 4 = 0

In order to solve for that, {let}^{'} s first take

a look on what are the values of a, b and c

{1 x}^{2} + 5 x + 4 = 0

a = 1; b = 5; c = 4

Now, using the quadratic formula

x = \frac{- 5 \pm \sqrt{5^{2} - 4 (1) (4)}}{2 (1)}

= \frac{- 5 \pm \sqrt{25 - 16}}{2}

= \frac{- 5 \pm 3}{2}

Answered by Mr.D.N. last updated on 28/Aug/22

x^{2} + 5 x + 4 = 0

x^{2} + 2 . \frac{5}{2} . x + \frac{25}{4} - \frac{25}{4} + 4 = 0

{(x + \frac{5}{2})}^{2} = \frac{25}{4} - 4

{(x + \frac{5}{2})}^{2} = \frac{9}{4}

(x + \frac{5}{2}) = \underline{+} \sqrt{{(\frac{3}{2})}^{2}}

x = - \frac{5}{2} \overset{+}{-} \frac{3}{2}

x = \frac{- 5 \overset{+}{-} 3}{2} / / .

Facebook Tweet Pin