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ax2-bx-c-0-

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Question Number 16919 by rustylee last updated on 28/Jun/17
ax2+bx+c=0
ax2+bx+c=0
Answered by RasheedSoomro last updated on 28/Jun/17
ax^2 +bx+c=0⇒ x=((−b±(√(b^2 −4ac)))/(2a))
ax2+bx+c=0⇒x=−b±b2−4ac2a

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