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ax2-bx-c-0-




Question Number 16919 by rustylee last updated on 28/Jun/17
ax2+bx+c=0
$${ax}\mathrm{2}+{bx}+{c}=\mathrm{0} \\ $$
Answered by RasheedSoomro last updated on 28/Jun/17
ax^2 +bx+c=0⇒             x=((−b±(√(b^2 −4ac)))/(2a))
$${ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0}\Rightarrow \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{x}=\frac{−{b}\pm\sqrt{{b}^{\mathrm{2}} −\mathrm{4}{ac}}}{\mathrm{2}{a}} \\ $$

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