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B-3-2B-2-4B-8-y-0-solve-the-differencial-equation-




Question Number 148939 by Rankut last updated on 01/Aug/21
 (B^3 −2B^2 −4B+8)y=0  solve the differencial equation
$$\:\left({B}^{\mathrm{3}} −\mathrm{2}{B}^{\mathrm{2}} −\mathrm{4}{B}+\mathrm{8}\right){y}=\mathrm{0} \\ $$$${solve}\:{the}\:{differencial}\:{equation} \\ $$

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